2010-12-23
3,458 reads
2010-12-23
3,458 reads
I have added 2 functions here, one for email validation and another to split the string by specified separator by user.
2010-12-23 (first published: 2010-12-11)
1,695 reads
A Stored Procedure for your tools database. It lists uncompressed tables and indexes and also generates the SQL to compress them.
2010-12-22 (first published: 2009-08-27)
950 reads
Report unusual conditions that may be filling up your transaction log.
2010-12-22
534 reads
A generic character padding function. Useful for situations where you need fixed width formatting e.g. email reports.
2010-12-20 (first published: 2010-03-31)
2,308 reads
Script to get a list of publications an article is in
2010-12-17 (first published: 2010-12-08)
3,786 reads
This script reveals the state of your indexes. It breaks down the indexes where they are partitioned, matching the index to it’s partition and filegroup.
2010-12-16 (first published: 2010-04-22)
7,574 reads
This function evaluates the statement like '4+5*6-3' and returns the numeric value.It is just like Eval funcction in javascript.
2010-12-15 (first published: 2010-12-08)
1,061 reads
2010-12-14 (first published: 2010-11-30)
3,851 reads
Script to grant exec permission to all sps in a db
2010-12-13 (first published: 2010-12-09)
1,733 reads
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
By ChrisJenkins
Have you been thinking about migrating your reporting to Microsoft Fabric or Snowflake but...
The Joyful Craftsmen has become the new owner of Revolt BI. The merger creates...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
Comments posted to this topic are about the item SQL Server Enum Implementation: A...
Comments posted to this topic are about the item BIT_COUNT I
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers