The Bones of SQL - The Holiday Table
This second part to a previous article on Calendar table generation shows how to create a holiday table containing both fixed-date and variable-date holidays.
This second part to a previous article on Calendar table generation shows how to create a holiday table containing both fixed-date and variable-date holidays.
Microsoft announced the release or CTP 2.1 for SQL Server 2019. This is the second CTP released for SQL Server 2019, and it has lots of new exciting features, like " UDF inlining". Read on to find out more!
Creating forms is one of the most basic skills for a web developer. It’s easy to, do but achieving the best user experience takes some work. In this article, Dino Esposito demonstrates how to improve the usability and functionality of web forms.
There are times when you need to share tables between servers, where the table may be updated in both places. Peer-to-Peer Transactional Replication gives you the ability to create a solution. I explain the benefits and the downfalls.
Learn how to stop the data sync process in SQL Server Merge Replication on a large table during maintenance windows.
With a data breach at Marriot, there is a call from one person for companies to spend more on security.
Problems with data quality are easier and cheaper to prevent than to solve later. In this article, Joe Celko talks about data quality and where the issues tend to happen.
By Chris Yates
In the beginning, there was OLTP – Online Transaction Processing. Fast, reliable, and ruthlessly...
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Hello SQL Server 2022 16.0.4212.1 running on a Windows Server 2025 Std,V 24H2, SO...
i have subscription of github copilot which i can access in vs 2022 comunity...
Comments posted to this topic are about the item Password Guidance
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers