SQL and the JOIN Operator
How the JOIN operator works, the different types of JOINs and relevant information about joining tables.
2011-03-03 (first published: 2009-10-07)
47,613 reads
How the JOIN operator works, the different types of JOINs and relevant information about joining tables.
2011-03-03 (first published: 2009-10-07)
47,613 reads
Retrieve consecutive records from the table based the value difference
2009-11-04 (first published: 2009-10-06)
949 reads
2009-10-02
4,634 reads
2009-10-21 (first published: 2009-10-01)
2,303 reads
In development enviornment we always get the modifications in tables from developers.As far as my concern writing scripts is tedious work for us. I hope below script will help you.
2009-10-30 (first published: 2009-10-01)
1,349 reads
2009-10-01
4,179 reads
Joe Celko comes back with a puzzle that isn't new, but one where the answer he originally gave now seems archaic: It is a deceptively simple problem, but is it true that the new features of SQL have simplified the solution? We leave it to the readers to provide the answer!
2009-09-28
3,535 reads
2009-09-25
3,569 reads
SQL WHERE clause optimization is important to get maximum performance from a query. If an index exists on a column you obviously want the query to use it...
2009-09-25
9,654 reads
2009-09-24
4,678 reads
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
By ChrisJenkins
Have you been thinking about migrating your reporting to Microsoft Fabric or Snowflake but...
The Joyful Craftsmen has become the new owner of Revolt BI. The merger creates...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
Comments posted to this topic are about the item SQL Server Enum Implementation: A...
Comments posted to this topic are about the item BIT_COUNT I
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers