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SQLServerCentral Article

New 64-bit sqlSentry Enhances Performance and Scalability

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sqlSentry, a leading developer of management solutions for Microsoft SQL Server, today announced that it has released the 64-bit version of its industry-leading scheduling and notification management system for SQL Server 2005, supporting both x64 and Itanium-based systems.

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2006-01-11

2,715 reads

SQLServerCentral Article

BDS SQL Digger 2 Released

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Have you ever needed to find something in a stored procedure or function and found yourself trying to wade through syscomments? Ever want to know which views reference a table, but you don't trust sysdepends? BDS has released SQL Digger 2.0, a utility designed to help you search through your schema and code to find what you need.

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2005-04-18

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External Article

Maintained by man and dog

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As the online news service called NewsScape moves into its sixth year, it exhibits a lot of the characteristics of a child at the same age: It has a huge appetite for information, grows by leaps and bounds each year, and makes those who oversee it wonder if they can maintain control as it gets bigger. It is maintained by "a man and a dog – an aging golden retriever named Sambucus," according to the man, Andrew Clarke.

2005-04-15

1,744 reads

SQLServerCentral Article

BDS SQL Digger 2.0 Released

  • Article

Have you ever needed to find something in a stored procedure or function and found yourself trying to wade through syscomments? Ever want to know which views reference a table, but you don't trust sysdepends? BDS has released SQL Digger 2.0, a utility designed to help you search through your schema and code to find what you need.

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2005-04-05

3,826 reads

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Question of the Day

Adding new column with DEFAULT

Which number will the COUNT() return after executing the following statements:

DROP TABLE IF EXISTS #test;
CREATE TABLE #test (id INT)
INSERT INTO #test (id)
SELECT *
  FROM GENERATE_SERIES(1, 3) AS gs
;

ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0;
go
UPDATE #test SET flag = 0 WHERE id = 1
UPDATE #test SET flag = 1 WHERE id = 2

INSERT INTO #test (id) VALUES (4)

SELECT COUNT(*)
  FROM #test AS t
 WHERE flag = 0
 

See possible answers