JSON Has a Cost
JSON has become a very popular data format used in many software applications. However, it's not magic.
2026-01-14
260 reads
JSON
How to Query JSON Data Quickly in SQL Server, Part 1: Pre-2025
Before SQL Server 2025, if you want to store JSON data in Microsoft SQL Server or Azure SQL DB, and you want fast queries, the easiest way is to:
2025-11-28
Techniques to query Azure SQL’s new JSON Datatype
The new JSON field type and new functions in Azure SQL brings a new world of possibilities for JSON manipulation in SQL Databases. These features are slated to be a part of SQL Server 2025 as well. Let’s analyze some practical uses of these features
2025-06-09
SQL Server JSON Functions JSON_OBJECTAGG and JSON_ARRAYAGG
I need to construct JSON from data in our database, but I find the existing FOR JSON PATH limited when the data is not located in one single row but rather scattered over multiple rows. Is there another method on how to handle JSON data in SQL Server? Learn how to use the new SQL Server JSON Functions JSON_OBJECTAGG and JSON_ARRAYAGG in this article.
2025-03-24
2025-02-28
468 reads
Effective Strategies for Storing and Parsing JSON in SQL Server
Like XML, JSON is an open standard storage format for data, metadata, parameters, or other unstructured or semi-structured data. Because of its heavy usage in applications today, it inevitably will make its way into databases where it will need to be stored, compressed, modified, searched, and retrieved.
2024-09-09
JQ - Tool for Querying JSON documents using the CLI
Learn how you can query JSON data from a CLI to check it before importing the data into a database.
2024-02-16
8,726 reads
2023-10-25
580 reads
2023-06-19
564 reads
2021-09-17
561 reads
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Question of the Day
Using CHOOSE()
We have this code that sets some status values and then queries them using the CHOOSE() function in SQL Server 2025.
CREATE TABLE Status
(
StatusID INT,
StatusDescription VARCHAR(20)
);
GO
INSERT dbo.Status
(
StatusID,
StatusDescription
)
VALUES
(0, 'Uncategorized'),
(1, 'Active'),
(2, 'Inactive'),
(3, 'Temp');
GO
SELECT CHOOSE(StatusID, 'Unknown', 'Active', 'Inactive', 'Temporary')
FROM Status;
When the SELECT runs, what is returned? See possible answers