e-Readers - $50?
I don’t think this survey was done well. Most people want an e-reader for $50, according to the survey. That’s...
2009-09-05
514 reads
I don’t think this survey was done well. Most people want an e-reader for $50, according to the survey. That’s...
2009-09-05
514 reads
Over the last few weeks I’ve had several instances where I’ve had to learn new things and, in my struggles,...
2009-09-05
473 reads
Starting Saturday, September 26, 2009, I will begin a 30 day, 9 city, and 11 session speaking tour of Australia...
2009-09-04
651 reads
Here is a very good blog post from Aaron Bertrand (another SQL MVP) on how to write and format stored...
2009-09-04
948 reads
They should have done this on day 1 of the issue: offer users a legitimate copy and move their annotations....
2009-09-04
578 reads
On Monday August 1st I had the pleasure of speaking to a group of college students that all belong to...
2009-09-04
399 reads
Well looks like I will be packing my bags for Sunny Orlando. I Just found out that my abstract was...
2009-09-04
415 reads
Tia and I were moving dirt around the ranch this weekend. It was a chore that needed to be done,...
2009-09-04
346 reads
Job Market Update and some Job Search Advice…..
Not too long ago, I posted a blog on the possible thawing of...
2009-09-04
1,418 reads
The new book is up on Amazon. I only worked on three chapters of Rob Walter’s new book and that...
2009-09-04
630 reads
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
By Zikato
A cryptic message, a book cipher hidden in art provenance records, and a trail...
I have a need to execute a stored procedure and return the results to...
Title pretty much says it all - can this be done? I've tried several...
Comments posted to this topic are about the item BIT_COUNT II
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers