SQL New Blogger Challenge: Week 1 recap
Thanks to everyone who participated in week 1 of the SQL New Blogger Challenge! Eight posts were written this week...
2015-11-07
198 reads
Thanks to everyone who participated in week 1 of the SQL New Blogger Challenge! Eight posts were written this week...
2015-11-07
198 reads
Thanks to everyone who participated in week 1 of the SQL New Blogger Challenge! Eight posts were written this week...
2015-11-07
186 reads
Week 1 of the November 2015 SQL New Blogger Challenge is behind us, and I saw some great posts. Now,...
2015-11-09 (first published: 2015-11-05)
814 reads
Week 1 of the November 2015 SQL New Blogger Challenge is behind us, and I saw some great posts. Now,...
2015-11-05
222 reads
Week 1 of the November 2015 SQL New Blogger Challenge is behind us, and I saw some great posts. Now,...
2015-11-05
284 reads
The week of the PASS Summit is always one of the highlights of my year. Even though I keep connected...
2015-11-04
394 reads
The week of the PASS Summit is always one of the highlights of my year. Even though I keep connected...
2015-11-04
276 reads
The week of the PASS Summit is always one of the highlights of my year. Even though I keep connected...
2015-11-04
285 reads
It’s already time for week 1 of this round of the SQL New Blogger Challenge! I have to admit that...
2015-11-03
368 reads
A little over six months ago, I suggested the SQL New Blogger Challenge. I thought that maybe a few people...
2015-10-27
443 reads
By Steve Jones
I’m not sure I knew identity column values could not be updated. I ran...
By Steve Jones
We had an interesting discussion about deployments in databases and how you go forward...
By ChrisJenkins
You could be tolerating limited reporting because there isn’t an off the shelf solution...
I have mentioned this several times over several years. Can someone please help me...
SELECT COUNT(DISTINCT Component) AS Found FROM tblComponents WHERE(Component NOT LIKE '%[a-z]%') AND(LTRIM(RTRIM(Component)) = 'GM13622')...
Comments posted to this topic are about the item Remotely Engineer Fabric Lakehouse objects:...
In a SQL Server 2025 table, called Beer, I have this data:
BeerIDBeerName 1Becks 2Fat Tire 3Mac n Jacks 4Alaskan Amber 8KirinI run this code:
SELECT JSON_OBJECTAGG(
BeerID: BeerName )
FROM beer;
What are the results? See possible answers