Reblog: October 10 to October 16
Photo credit – JStove
Old posts are like unicorns. You might see them just once, but it’d sure be nice to have...
2014-10-17
705 reads
Photo credit – JStove
Old posts are like unicorns. You might see them just once, but it’d sure be nice to have...
2014-10-17
705 reads
It’s Monday time for this week’s weekly link round-up. If you want to catch these links “live” (so exciting), follow...
2014-10-13
1,048 reads
Photo credit – Travis
Ever go digging through your backyard for dinosaur bones? Maybe not, but it’s worthwhile from time to time...
2014-10-10
965 reads
Photo credit – Husso
I’ve always been a fan of the feeling when I find an old blog post that’s got just...
2014-10-03
829 reads
Photo credit – Mike Lynch
A good cure to a creepy doll is a good old post that is still useful. In...
2014-09-26
786 reads
Photo credit – Jenn and Tony Bot
Sometimes old stuff is just as cool as new stuff. Over the past few years,...
2014-09-19
740 reads
Photo credit – JStove
Old posts are like unicorns. You might see them just once, but it’d sure be nice to have...
2014-09-12
796 reads
Photo credit – Travis
Ever go digging through your backyard for dinosaur bones? Maybe not, but it’s worthwhile from time to time...
2014-09-05
731 reads
It’s Monday time for this week’s weekly link round-up. If you want to catch these links “live” (so exciting), follow...
2014-09-01
351 reads
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It’s time for a monthly reminder to review you SQL Server environment. As with anything, just because it appears...
2014-09-01
494 reads
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
SELECT * feels convenient, but in SQL Server it bloats I/O, burns network bandwidth,...
Comments posted to this topic are about the item Cleaning Up the Cloud
Comments posted to this topic are about the item The Maximum Value in the...
Comments posted to this topic are about the item Oracle Performance Tuning: Practical Techniques...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers