TSQL Sudoku II
As luck would have it, today I came across this TSQL Challenge. It just so happens that I had already...
2011-08-23
1,075 reads
As luck would have it, today I came across this TSQL Challenge. It just so happens that I had already...
2011-08-23
1,075 reads
Learn how to solve Sudoku puzzles quickly with a TSQL Script.
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2011-08-23
1 reads
SQL Saturday 94 in Salt Lake City is fast approaching. Will you be there? I submitted three sessions in hopes...
2011-08-22
678 reads
SQL Saturday 94 in Salt Lake City is fast approaching. Will you be there? I submitted three sessions in hopes of maybe getting one selected. Last year, I only...
2011-08-22
2 reads
Some time ago, I wrote an introductory post about bitwise operations in SQL Server. I had fully intended on writing...
2011-08-19
1,594 reads
Some time ago, I wrote an introductory post about bitwise operations in SQL Server. I had fully intended on writing a follow-up to that. Alas the opportunity has passed...
2011-08-19
1 reads
By now, you have heard of subqueries. You have also heard of Common Table Expressions. I am sure you know...
2011-08-18
907 reads
By now, you have heard of subqueries. You have also heard of Common Table Expressions. I am sure you know what a derived table is and that you get...
2011-08-18
18 reads
I am a big Sudoku fan. Typically if I need a break, I will break out a Sudoku puzzle from...
2011-08-17
1,028 reads
I am a big Sudoku fan. Typically if I need a break, I will break out a Sudoku puzzle from any of a number of different sources (Websudoku, Android...
2011-08-17
4 reads
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Comments posted to this topic are about the item Cleaning Up the Cloud
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers