Voting for the PASS Board
I got the email with a Zoomerang survey to vote for the PASS board. All are excellent candidates, but ultimately,...
2008-11-18
956 reads
I got the email with a Zoomerang survey to vote for the PASS board. All are excellent candidates, but ultimately,...
2008-11-18
956 reads
2008-11-18
652 reads
How many mirrrored databases can I have on a server?
10 mirrored databases per server is the recommendation for a 32...
2008-11-18
6,455 reads
Speaker: Paul Shearer
Midlands PASS Chapter - December 4, 2008 Meeting
The Midlands PASS chapter will hold our normally scheduled meeting on Thursday,...
2008-11-18
580 reads
I endorsed Andy Warren for the board the other day, and I'll stand by that. I'm biased, so if you're...
2008-11-18
1,257 reads
I don't mean to comlpain, and I certainly don't need any more bags, but when I checked in Monday night...
2008-11-18
651 reads
Fairly easy day, up at 5 am for an 8:15 am flight to Seattle via Detroit, arrived about 2:30 pm...
2008-11-17
536 reads
OK, I'm biased. I'll admit it and you have every right to discount my endorsement, but I'll make the case...
2008-11-17
717 reads
I've been in Seattle since Friday afternoon and I've pretty much ignored SQL Server. And it's been nice!
I came up...
2008-11-16
642 reads
This is what I provided to the nominating committee today. I think I could have worked on this for weeks...
2008-11-16
1,436 reads
By James Serra
Microsoft shared a broad set of Fabric, Power BI, and SQL updates at FabCon...
By Steve Jones
No, I’m not quitting or retiring. Just going on vacation, but I leave tonight...
Comments posted to this topic are about the item Let's Talk Certifications, which is...
Comments posted to this topic are about the item The Hidden Security Risks of...
Comments posted to this topic are about the item The Empty Aggregate
I have this table in a SQL Server 2025 database:
CREATE TABLE [dbo].[CustomerOrder] ( [OrderID] [int] NULL, [CustomerID] [int] NULL, [total] [money] NULL ) ON [PRIMARY] GOWhat is returned from this code? (answers are for the sum and then the count)
SELECT SUM(total) AS sum,
COUNT(total) AS count
FROM dbo.CustomerOrder;
See possible answers