Colorado SQL Events for June 2014
All ColoradoSQL user group meetings start at 5:30 p.m. and provide food and refreshments. There is no cost to attend...
2014-06-10
484 reads
All ColoradoSQL user group meetings start at 5:30 p.m. and provide food and refreshments. There is no cost to attend...
2014-06-10
484 reads
Whenever a disaster occurs it will be a stressful scenario regardless of how small or big the disaster is. This gets multiplied...
2014-06-09
766 reads
Sunday I spent an hour going over various notes and thinking about what I’ve seen in the past couple PASS...
2014-06-09
354 reads
Steps for SQL Server 2014 Cluster Installation – Add Node to Failover Cluster:-
1) Lunch SQL Server Installation Center
2) Enter Product Key
3)...
2014-06-09
2,428 reads
It’s Monday time for this week’s weekly link round-up. If you want to catch these links “live” (so exciting), follow...
2014-06-09
912 reads
The results were posted Friday afternoon, I placed second in the voting with 214 votes from a total of 539...
2014-06-09
450 reads
Being in Philadelphia this past weekend was fantastic! I got to meet a lot of old friends, spend time with...
2014-06-09
611 reads
For the second time this year, Dell Software has invited me to present as part of the webinar series on...
2014-06-09
561 reads
A little while back Michael J Swart(B/T) offered to help you become a better writer. This was exciting for me...
2014-06-09
891 reads
(Be sure to checkout the FREE SQLpassion Performance Tuning Training Plan – you get a weekly email packed with all the...
2014-06-09
1,615 reads
By Steve Jones
My life has some crazy travel stretches for sure. Between speaking, office visits, customer...
In Part 1, we saw how ‘Vamana’ represents vectors as nodes, connects them with...
I’m excited to announce the release of a new open-source project that fully automates...
Comments posted to this topic are about the item Server-Level Table sizes
Comments posted to this topic are about the item Optional Parameter Plan Optimization in...
There is a table tmp_tab:
CREATE TABLE tmp_tab ( id int, val int );
INSERT INTO tmp_tab VALUES (1, 1), (2, NULL), (3, 3), (4, 4), (5, 5);You want to order the rows ids by the following expression:
ISNULL(val, id) + 1Which of the following queries produces the expected ordering and why? (Select all correct) See possible answers