SQLSaturday Update - 215 Registered!
We're at 215 registered with 3 weeks to the big day! This week I'll be having the last planning meeting...
2007-10-21
1,461 reads
We're at 215 registered with 3 weeks to the big day! This week I'll be having the last planning meeting...
2007-10-21
1,461 reads
The most recent ACM Queue Magazine (Vol 5 #6, Sep/Oct 2007) had two really interesting articles. The first was about...
2007-10-21
1,513 reads
I wrote this article shortly after returning from the PASS 2007 Summit and tried hard to come up with ideas...
2007-10-18
1,349 reads
Here's a good article on setting up Deadlock Notifications in SQL Server 2005 written by Patrick LeBlanc.
2007-10-16
1,485 reads
All of these are new articles that have gone up on SSC recently. The troubleshooting one was my attempt to...
2007-10-14
632 reads
Bill Graziano (main man at SQLTeam.com, consultant, and VP of PASS) was in town recently to speak at both the...
2007-10-13
685 reads
I'm catching up on my reading today and ran across an article from Kathi Kellenberger called Understanding the Difference between...
2007-10-13
605 reads
I'm a couple days late updating the blog, the article went up on Mon.
2007-10-11
573 reads
I spent last week onsite with a client teaching performance tuning and it was really a good week. Great company...
2007-10-08
608 reads
I hate contests. I mean it's nice to get people involved and I start out with the best of intentions...
2007-10-07
730 reads
By Zikato
A cryptic message, a book cipher hidden in art provenance records, and a trail...
By Steve Jones
A customer was trying to compare two tables and capture a state as a...
By Zikato
When I'm looking at a query, I bet it's bad if I see... a...
Best Inspection and Auditing Services of India focus on precision, quality control, and compliance,It...
WA:08218154393 Jl. Surabaya No.88 B-C, Ps. Baru, Kec. Medan Kota, Kota Medan, Sumatera Utara...
WA:08218154393 Jl. Perak Bar. No.267, Perak Utara, Kec. Pabean Cantian, Surabaya, Jawa Timur 60165
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers