Running Totals for Each Group
A while ago, I posted a blog on how one could perform running totals using Reporting Services and a user...
2010-10-11
4,396 reads
A while ago, I posted a blog on how one could perform running totals using Reporting Services and a user...
2010-10-11
4,396 reads
Presenting is a huge fear for many and it is no different for me. I have been presenting at SQL...
2010-10-10
591 reads
Recently, I came across a forum post from a user trying to determine if a directory existed in the file...
2010-10-06
14,368 reads
It's official! I am presenting a mini session for SQL Saturday in Orlando. My topic and some details are below:
Delivery...
2010-10-05
462 reads
Have you ever queried the msdb tables to get duration details about a particular job? I’ve had to do this...
2010-10-05
2,778 reads
While working on a project recently, I came across a conversion that was trying to convert a date to an...
2010-10-05
808 reads
Here is another one of those strange but true things that I come across every so often which I thought...
2010-10-01
1,518 reads
The way Reporting Services creates subscriptions is through generating a SQL Server Agent job. This is apparent when you look...
2010-09-01
796 reads
A colleague of mine and I were recently talking about some scripts that they had seen containing the WITH NOLOCK...
2010-09-01
546 reads
Over the many years that I’ve been dealing with SQL Server, I’ve always been told and read about how using...
2010-08-29
610 reads
Programmatic Tool Calling with the Claude SDK Every morning somebody on the team runs the...
By Steve Jones
mauerbauertraurigkeit – n. inexplicable urge to push people away, even close friends whose company...
By Brian Kelley
Pinal Dave wrote up his methodology for what to do when you discover bad...
Comments posted to this topic are about the item Why SQL Server Database Attach...
Comments posted to this topic are about the item Fixing P1 Queries
Comments posted to this topic are about the item BIT_COUNT() IV
In SQL Server 2025, I run this code:
select bit_count('A')
What is returned? See possible answers