T-SQL Tuesday #39 - Here's what my PoSH is cooking
My first official entry for T-SQL Tuesday (my first was a guest post hosted by Kendal Van Dyke (blog|twitter), so I’m not really counting it) is brought to you...
2013-02-12
1 reads
My first official entry for T-SQL Tuesday (my first was a guest post hosted by Kendal Van Dyke (blog|twitter), so I’m not really counting it) is brought to you...
2013-02-12
1 reads
2012-12-28
6 reads
I am a geek, husband, father, geocacher & gratuitous consumer of satellite signals (not in that order). I’ve been in IT professionally for over two decades doing web development,...
2012-12-04
4 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Comments posted to this topic are about the item The AI Bubble and the...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers