Blog Posts

Blog Post

Service Broker Blocking

This post is dedicated to all 10 other DBAs that use Service Broker (you know who you are).
The main reason for this blog post is that I’ve got no...

2024-08-19 (first published: )

170 reads

Blog Post

SQL Saturday Denver 2024 Resources

Here are the resources from my talks today. Best Practices for Seamless Database Deployments PPTX slides Architecting Zero Downtime Deployments git repo:  https://github.com/way0utwest/ZeroDowntime  PPTX slides Some good questions today,...

2024-08-18 (first published: )

41 reads

Blog Post

Kilt Day!

This is a quick blog post to announce that I am reviving Kilt Day at PASS Data Community Summit. Over the last few years… ah hell, let’s just say...

2024-08-16 (first published: )

127 reads

Blog Post

My Toolbox - SSMS

No matter how hard Azure Data Studio (ADS) is pushed by Microsoft, most DBAs still use SQL Server Management Studio (SSMS). In this blog post, I’ll go through my...

2024-08-14 (first published: )

863 reads

Blogs

Solving SQL Server Mysteries with a Whole Gang of Sleuths -Scooby Dooing Episode 4

By

One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...

SQL Server Availability Groups

By

Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...

Modify Power BI page visibility and active status with Semantic Link Labs

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Setting page visibility and the active page are often overlooked last steps when publishing...

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Forums

Password Guidance

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Password Guidance

Using table variables in T-SQL

By Alessandro Mortola

Comments posted to this topic are about the item Using table variables in T-SQL

Azure elastic query credential question

By cphite

I am trying to check out elastic query between two test instances we have...

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Question of the Day

Using table variables in T-SQL

What happens if you run the following code in SQL Server 2022+?

declare @t1 table (id int);

insert into @t1 (id) values (NULL), (1), (2), (3);

select count(*)
from @t1
where @t1.id is distinct from NULL;
 

See possible answers