May 2010 S3OLV Meeting Recap
On the evening of May 13th, S3OLV held its monthly meeting. We had some really good discussion, and got to...
2010-05-14
688 reads
On the evening of May 13th, S3OLV held its monthly meeting. We had some really good discussion, and got to...
2010-05-14
688 reads
A friend of mine had been out to the Microsoft Certified Architect site recently and noted that the Infrastructure and...
2010-05-14
1,957 reads
SQL Server Azure database supports the T-SQL, but no at all! For the SQL Server Azure and T-SQL are available...
2010-05-14
8,710 reads
Using configurations files in SSIS is a great way to change how your package will run from outside the development...
2010-05-14
863 reads
A friend is moving into a leadership role for the first time and we talked some about making that transition....
2010-05-14
951 reads
Thomas LaRock (SQL Server MVP) (Blog | Twitter | LinkedIN), recently has published the new book DBA Survivor: Become a Rock Start...
2010-05-14
815 reads
In April, I ran a Question of the Month that asked, “What advice would you offer a novice DBA in...
2010-05-13
968 reads
Every day for the next couple of weeks, I aim to highlight one of SQL Server 2008’s new features, simply...
2010-05-13
554 reads
I was getting tired of pre-formatting code in LiveWriter. I love that software, but a couple of the technical things...
2010-05-13
924 reads
On my current project I decided to be flexible and allow the use of Linq to SQL to try to...
2010-05-13
270 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers