Tools Only Help
“Building an easy-to-use tool does not make an amateur more skilled at making applications and more than a $900 table...
2010-08-10
787 reads
“Building an easy-to-use tool does not make an amateur more skilled at making applications and more than a $900 table...
2010-08-10
787 reads
I almost forgot about T-SQL Tuesday this time, so I’m scrambling to get an entry done today.
This is a...
2010-08-10
837 reads
T-SQL Tuesday #009: Beach Time: My Work Away From Work
This blog entry is participating in T-SQL Tuesday #009, hosted...
2010-08-10
678 reads
Someone posted a note asking how they might restore if the disk that contained their transaction log crashed. I replied...
2010-08-09
412 reads
Not sure if anyone else posted about this, but just sharing the news of the R2 Management Pack from MSDN:
"Following...
2010-08-09
1,383 reads
Kendal Van Dyke blogged about it last week here, we ended up with 3 great designs to pick from for...
2010-08-09
333 reads
Hey folks - Dont 'forget to check out SQL Lunch today. I'm hosting Mr. Andy Leonard! Always exciting and cool information.....
2010-08-09
397 reads
Things have worked out where I'll be able to hit a SQL Saturday for this month and each of the next...
2010-08-09
601 reads
Pirate Cat can haz ur Swag?
Well it’s the first Monday back since this amazing trip and some folks have wasted...
2010-08-09
661 reads
One of the things I think we don’t do well sometimes – in generally – is set fair expectations with regards to...
2010-08-09
658 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
Many years ago, before I joined Oracle, I was working on a major modernisation...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
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In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers