Tracy Boggiano

Tracy is the Database Superhero for ChannelAdvisor. She has spent over 20 years in IT and has used SQL Server since 1999. Tracy covers all aspects of administration and deals heavily with performance tuning and high availability and disaster recovery. Tracy is a co-organizer of a Special Interest Group (SIG) dedicated to advanced DBA topics in our local user group TriPass. She is also the founder of http://WeSpeakLinux.com. Before she worked full-time as a DBA she was formally a developer and network administrator. She also tinkered with databases in middle/high school to keep her sports card collection organized.

All authors

All authors

Blogs

Cost Visibility: Tracking and Analysing Your Cloud Spend

By

One of the biggest challenges I’ve faced in cloud operations is maintaining clear visibility...

Whiling away an afternoon, thinking

By

I come to Heathrow often. Today is likely somewhere close to 60 trips to...

Black Box vs. Gray Box vs. White Box Testing

By

If your organization is spending money, then meaningful results are a must. Pen testing...

Read the latest Blogs

Forums

Fun with JSON II

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Fun with JSON II

Changing Data Types

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Changing Data Types

Answering Questions On Dropped Columns

By Cláudio Silva

Comments posted to this topic are about the item Answering Questions On Dropped Columns

Visit the forum

Question of the Day

Fun with JSON II

I have some data in a table: 

CREATE TABLE #test_data
(
    id INT PRIMARY KEY,
    name VARCHAR(100),
    birth_date DATE
);

-- Step 2: Insert rows  
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned? 
SELECT t1.[key] AS row,
       t2.*
FROM OPENJSON(
     (
         SELECT t.* FROM #test_data AS t FOR JSON PATH
     )
             ) t1
    CROSS APPLY OPENJSON(t1.value) t2;

See possible answers