John

John Morehouse is currently a Consultant with Denny Cherry & Associates living in Louisville, Kentucky. With over 2 decades of technical experience in various industries, John now focuses on the Microsoft Data platform and specializes in Microsoft SQL Server. He is honored to be a Microsoft Data Platform MVP, 2016 Idera Ace, Friend of Red Gate since 2015, Sentry One PAC member & Community Ambassador. John has passion around speaking, teaching technical topics and giving back to the technical community. He is a user group leader, SQL Saturday organizer, and former PASS regional mentor. He is also a blogger, avid tweeter, and a frequent speaker at SQL Saturday's as well as other conferences. If you want to find John, you can find him on Twitter (@sqlrus) or on his blog, http://sqlrus.com.

Blogs

Advice I Like: Respect

By

“Don’t aim to have others like you; aim to have them respect you.” –...

Blue Sky Programming – The Optimism Trap

By

Many years ago, before I joined Oracle, I was working on a major modernisation...

Setting Up a Mac for Data Engineering and AI Work

By

If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...

Read the latest Blogs

Forums

SQL Art, Part 4: Happy 4th of July — A British DBA's Guide to Celebrating a War We Don't Talk About

By Terry Jago

Comments posted to this topic are about the item SQL Art, Part 4: Happy...

Alamat Kantor BCA KCU KUDUS Telp:0817839777

By R4nt4u

WhatsApp: 0817839777 Jl. Jend. Ahmad Yani No.91, Magersari, Panjunan, Kec. Kota Kudus, Kabupaten Kudus,...

Alamat Kantor BCA KCU SEMARANG Telp:0817839777

By layanan_Bca88

WhatsApp: 0817839777 Jl. Pemuda No.90-92, Kembangsari, Kec. Semarang Tengah, Kota Semarang, Jawa Tengah 50133

Visit the forum

Question of the Day

BIT_COUNT I

In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:

UserID  UserPermissions
15
23
37
What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount
from dbo.UserPermission
where UserID = 3;

See possible answers