Use of SQL server statistics and how to make a query to use them
Statistics are very important in the query...
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2019-09-04
193 reads
Statistics are very important in the query...
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2019-09-04
193 reads
How to read execution plan to improve poorly...
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2019-08-25
173 reads
Requirement: Remove a node from one of...
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2019-07-17
116 reads
The index is very important and powerful object...
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2019-07-03
176 reads
Migration is nothing but moving a databases from...
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2019-06-05
252 reads
SQL server upgrade is going lower version of SQL...
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2019-05-08
47 reads
File and file group VLDB very large database....
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2019-04-03
35 reads
Problem: SQL server database refresh / restore...
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2019-03-20
370 reads
Problem: SQL server database refresh / restore...
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2019-03-20
19 reads
SQL server reports GUI Schema change history and...
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2019-03-06
409 reads
By Steve Jones
This value is something that I still hear today: our best work is done...
By gbargsley
Have you ever received the dreaded error from SQL Server that the TempDB log...
By Chris Yates
Artificial intelligence is no longer a distant concept. It is here, embedded in the...
Comments posted to this topic are about the item Planning for tomorrow, today -...
We have a BI-application that connects to input tables on a SQL Server 2022...
At work we've been getting better at writing what's known as GitHub Actions (workflows,...
I try to run this code on SQL Server 2022. All the objects exist in the database.
CREATE OR ALTER VIEW OrderShipping AS SELECT cl.CityNameID, cl.CityName, o.OrderID, o.Customer, o.OrderDate, o.CustomerID, o.cityId FROM dbo.CityList AS cl INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID GO CREATE OR ALTER FUNCTION GetShipCityForOrder ( @OrderID INT ) RETURNS VARCHAR(50) WITH SCHEMABINDING AS BEGIN DECLARE @city VARCHAR(50); SELECT @city = os.CityName FROM dbo.OrderShipping AS os WHERE os.OrderID = @OrderID; RETURN @city; END; goWhat is the result? See possible answers