Koen Verbeeck

Koen Verbeeck is a Microsoft Business Intelligence consultant at AE, helping clients to get insight in their data. Koen has comprehensive knowledge of the Microsoft Data Platform and has been a Microsoft Data Platform MVP for several years. He's also a speaker at various conferences.

Blog Post

How I passed the DP-700 Exam

I recently took and passed the DP-700 exam, which is required for the Microsoft Certified: Fabric Data Engineer Associate certification. It’s the second Fabric certification, and it focuses more...

2025-03-17 (first published: )

1,030 reads

Blog Post

Cloudbrew 2024 – Slides

You can find the slides for the session Building the €100 data warehouse with the Azure Data Platform in this GitHub repo.
The post Cloudbrew 2024 – Slides first appeared...

2024-12-13

22 reads

Blogs

In-Person CISA Training – April 13-16, 2026

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I will be leading an in-person Certified Information Systems Auditor (CISA) exam prep class...

EightKB 2026

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EightKB is back again for 2026! The biggest online SQL Server internals conference is...

The FinOps Lifecycle: From Budgeting to Reporting

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Working in DevOps long enough teaches you two universal truths: That’s exactly why I...

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Forums

VS Code, Unresolved References.

By mjdemaris

Hi all, I just started using VS Code to work with DB projects.  I...

Fun with JSON II

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Fun with JSON II

Changing Data Types

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Changing Data Types

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Question of the Day

Fun with JSON II

I have some data in a table:

CREATE TABLE #test_data
(
    id INT PRIMARY KEY,
    name VARCHAR(100),
    birth_date DATE
);

-- Step 2: Insert rows  
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
       t2.*
FROM OPENJSON(
     (
         SELECT t.* FROM #test_data AS t FOR JSON PATH
     )
             ) t1
    CROSS APPLY OPENJSON(t1.value) t2;

See possible answers