Joyful Crafsmen is a young company designing, constructing and operating business intelligence solutions for enterprises. People behind are experts in Microsoft Data Platform, which includes SQL Server, Microsoft Azure, Power BI and other leading edge Microsoft technologies. Sharing our know-how with others is our other love. Through training, consulting, and teaching in our community, we help others to be better and better every day.

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Tech Lunch News

Červencové novinky ze světa dat byly trochu prázdninové a odpočinkové, ale i tak jsme se podívali na pár zajímavých a šikovných demíček, které by se vám mohli hodit.
Co nového...

2023-07-19

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Power BI Tracker

Znáte ten pocit, kdy jste si přepsali nějakou složitější measure a rádi byste jí vrátili do stavu, jak vypadala před hodinou? Nebo kolega něco upravil ve vašem modelu, ale...

2022-09-22 (first published: )

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Blog Post

Azure Synapse Case Study

Let’s introduce our customer and their product
Our client is working in telecommunications providing secure and reliable networks. They are an independent supplier of mobile, data and voice services in...

2022-06-29 (first published: )

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Blogs

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Forums

Refactoring SQL Code

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Refactoring SQL Code, which is...

The Read Committed Snapshot Isolation behaviour

By Alessandro Mortola

Comments posted to this topic are about the item The Read Committed Snapshot Isolation...

Working with JSON/JSONB Data in PostgreSQL using Python

By sabyda

Comments posted to this topic are about the item Working with JSON/JSONB Data in...

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Question of the Day

The Read Committed Snapshot Isolation behaviour

I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:

use master;
go

alter database AdventureWorks set read_committed_snapshot on with no_wait;
go
Then, from Session 1, I execute the following code:
--Session 1
use AdventureWorks;
go

create table ##t1 (id int, f1 varchar(10));
go

insert into ##t1 values (1, 'A');
From another session, called Session 2, I open a transaction and execute the following update:
--Session 2
use AdventureWorks;
go

begin tran;
update ##t1 
set f1 = 'B'
where id = 1;
Now, going back to Session 1, what happens if I execute this statement?
--Session 1
select f1
from ##t1
where id = 1;
 

See possible answers