2012-01-18
10 reads
2012-01-18
10 reads
2011-08-24
12 reads
What are the most influential papers in the world of Big Data? Let me suggest:...
2011-05-30
9 reads
2011-05-02
5 reads
2011-02-02
8 reads
2011-01-05
7 reads
I searched the internet for “connect and forget”. Wonderbox.net offer is described as a...
2010-10-10
7 reads
10 years ago IT professionals considered database technology “mature” and analysts were preparing to...
2010-09-13
13 reads
“The information age is an idea that the current era will be characterized by the ability of...
2010-08-22
3 reads
“Content is king” is the golden rule of the SEO. The semantic web is all about data. Any web...
2010-06-25
11 reads
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
By DesertDBA
I haven’t posted in a while (well, not here at least since I’ve been...
Comments posted to this topic are about the item Refactoring SQL Code, which is...
Comments posted to this topic are about the item The Read Committed Snapshot Isolation...
Comments posted to this topic are about the item Working with JSON/JSONB Data in...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers