What Counts as Work - in Software Development
Bill explores the consequences of people not seeing the value in doing things that are crucial to the success of projects.
2013-12-11
544 reads
Bill explores the consequences of people not seeing the value in doing things that are crucial to the success of projects.
2013-12-11
544 reads
A look at what passes for technology from Bill Nicolich in our guest editorial.
2012-12-18
121 reads
A reflective editorial on how SharePoints and other collaborative work spaces are getting used.
2012-01-02
232 reads
Bill Nicolich raises questions about the chairs we sit in all day as technology professionals.
2009-07-29
123 reads
Meaningful change often requires information collection, processing, retrieval and distribution. As database professionals, that's our bag. So what can we do to help things along?
2008-09-17
185 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Comments posted to this topic are about the item The AI Bubble and the...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers