Basic PowerShell: Get-Member
Disclaimer: I’m still learning PowerShell. I’ve been using it more lately and I want to talk about it more. I’ll...
2019-01-08
304 reads
Disclaimer: I’m still learning PowerShell. I’ve been using it more lately and I want to talk about it more. I’ll...
2019-01-08
304 reads
This is post 3 in the series about query fingerprints. Here’s the previous posts in this series:
Query HashSQL Handle
What is...
2019-01-07
751 reads
I like public speaking, but I haven’t always liked it. It started when I read Dale Carnegie’s book on public...
2019-01-05
37 reads
Let’s talk about how queries use memory, specifically in the execution plan. One of the query operators that use memory...
2019-01-04
184 reads
If you’re on SQL Server 2016 or above, maybe you’re thinking about using the Query Store. That’s good! It’s an...
2019-01-03
1,473 reads
I know this post might sound obvious. This is a very rare problem. But this actually happened to me, and...
2019-01-02
42 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
hi, i noticed the sqlhealth extended event is on by default , and it...
Using New-AzSqlInstanceServerTrustCertificate to import a certificate and get the message New-AzSqlInstanceServerTrustCertificate: Long running operation...
Comments posted to this topic are about the item Refactoring SQL Code, which is...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers