Using a function to parse/return the Nth field of a delimited column
A useful SQL function to parse a single string with delimited values for the "N"th occurrence
2009-11-06 (first published: 2009-10-15)
1,419 reads
A useful SQL function to parse a single string with delimited values for the "N"th occurrence
2009-11-06 (first published: 2009-10-15)
1,419 reads
By Steve Jones
This value is something that I still hear today: our best work is done...
By gbargsley
Have you ever received the dreaded error from SQL Server that the TempDB log...
By Chris Yates
Artificial intelligence is no longer a distant concept. It is here, embedded in the...
Hi everyone I am writing an SP where there is logic inside the SP...
Comments posted to this topic are about the item Planning for tomorrow, today -...
We have a BI-application that connects to input tables on a SQL Server 2022...
I try to run this code on SQL Server 2022. All the objects exist in the database.
CREATE OR ALTER VIEW OrderShipping AS SELECT cl.CityNameID, cl.CityName, o.OrderID, o.Customer, o.OrderDate, o.CustomerID, o.cityId FROM dbo.CityList AS cl INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID GO CREATE OR ALTER FUNCTION GetShipCityForOrder ( @OrderID INT ) RETURNS VARCHAR(50) WITH SCHEMABINDING AS BEGIN DECLARE @city VARCHAR(50); SELECT @city = os.CityName FROM dbo.OrderShipping AS os WHERE os.OrderID = @OrderID; RETURN @city; END; goWhat is the result? See possible answers