Additional Articles


Technical Article

Database conversion between the most popular DBMSs

Today many companies determine to publish their data on the Internet trying to expand their business and make their information more accessible. The IT industry proposes a wide range of original solutions for resolving data inconsistency problems that publishers inescapably face when exporting their data as they need to properly access, process and interchange large amounts of information mainly through the web.

2008-12-30

2,236 reads

External Article

Finding a better candidate for your clustered indexes

When creating tables it is difficult to determine exactly how the data will be accessed. Therefore when clustered indexes are chosen they are often just the ID column that makes the row unique. This may be a good choice, but once the application has been used and data access statistics are available you may need to go back and make some adjustments to your tables to ensure your clustered indexes are providing a benefit and not a drain on your applications.

2008-12-26

3,880 reads

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Question of the Day

Changing the Schema

I set up a few users on my SQL Server 2022 instance.

CREATE LOGIN User1 WITH PASSWORD = 'Demo12#1'
CREATE USER User1 FOR LOGIN User1
GO
CREATE LOGIN User2 WITH PASSWORD = 'Demo12#2'
CREATE USER User2 FOR LOGIN User2
GO
CREATE LOGIN User3 WITH PASSWORD = 'Demo12#3'
CREATE USER User3 FOR LOGIN User3
GO
I then created a schema that one of them owned. Under this schema, I added a table with some data.
CREATE SCHEMA MySchema AUTHORIZATION User1
GO
CREATE TABLE Myschema.MyTable(myid INT)
GO
INSERT MySchema.MyTable
(
    myid
)
VALUES
(1), (2), (3)
GO
SELECT * FROM MySchema.MyTable
GO
I granted rights and verified that User2 could access this table.
GRANT SELECT ON Myschema.MyTable TO User2
GO
SETUSER 'USER2'
GO
SELECT * FROM MySchema.MyTable
GO
This worked. Now, I move this schema to a new user.
ALTER AUTHORIZATION ON SCHEMA::Myschema TO User3;
GO
What happens with this code?
SETUSER 'USER2'
GO
SELECT * FROM MySchema.MyTable
GO

See possible answers