Alexander Chigrik

I would like to offer consultation on MS-SQL by E-Mail

I am from Rostov-on-Don in Russia.I work for a firm Bis Ltd (Banking Information Systems) as a Microsoft SQL Server DBA and developer. I have more than 4 years solid experience
with version 6.5 and more than 2 years experience (since december 1998) with version 7.0.


Current Certifications:

  • Brainbench:Master MS SQL Server 6.5 Administration

  • Master MS SQL Server 6.5 Programming
  • Master MS SQL Server 7 Administration
  • Master MS SQL Server 7 Programming

All exams on Brainbench

I am in the list of 15 top experts on MS SQL under the version of experts-exchange:http://www.experts-exchange.com/jsp/qList.jsp?ta=mssql

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Technical Article

Generate Insert Statements Easily

This script will generate insert statements for the given tables. You can pass the tables names, separated by commas, into sp_DataAsInsCommand stored procedure as in the example below: EXEC sp_DataAsInsCommand 'employee,titleauthor,pub_info' Updated on 5/25/01 to correct an issue with columns that are short like a column defined as char(1), to correct another issue with the […]

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2001-08-09

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Question of the Day

The Read Committed Snapshot Isolation behaviour

I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON: 

use master;
go

alter database AdventureWorks set read_committed_snapshot on with no_wait;
go
Then, from Session 1, I execute the following code: 
--Session 1
use AdventureWorks;
go

create table ##t1 (id int, f1 varchar(10));
go

insert into ##t1 values (1, 'A');
From another session, called Session 2, I open a transaction and execute the following update: 
--Session 2
use AdventureWorks;
go

begin tran;
update ##t1 
set f1 = 'B'
where id = 1;
Now, going back to Session 1, what happens if I execute this statement? 
--Session 1
select f1
from ##t1
where id = 1;
 

See possible answers