Steve Jones

My background is I have been working with computers since I was about 12. My first "career" job in this industry was with network administration where I became the local DBA by default. I have also spent lots of time administering Netware and NT networks, developing software, managing smaller IT groups, making lots of coffee, ordering pizza for late nights, etc., etc.

I currently am the editor of SQL Server Central and an advocate/architect at Redgate Software. I am also the President of SQL Saturday, maintain the T-SQL Tuesday monthly party, and remember our colleagues at sqlmemorial.org.

You can find out more about me on my blog (www.voiceofthedba.com) or LinkedIn (www.linkedin.com/in/way0utwest)
  • Interests: yoga, reading, biking, snowboarding, volleyball

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SQLServerCentral Article

SQL Server 2022 Build List

This is a list of the builds for SQL Server 2022. There are other build lists available here. A list of all the builds that I can find and install on my Build VM. If you find a build not listed here, please let the webmaster know (webmaster at sqlservercentral.com). All builds are listed in reverse […]

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2026-05-21 (first published: )

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SQLServerCentral Article

SQL Server 2025 Build List

This is a list of the builds for SQL Server 2025. There are other build lists available here. A list of all the builds that I can find and install on my Build VM. If you find a build not listed here, please let the webmaster know (webmaster at sqlservercentral.com). All builds are listed in reverse […]

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2026-05-21 (first published: )

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Question of the Day

The string_agg function

We create the following table and then insert some records in it: 

create table t1 (
   id int primary key,
   category char(1) not null,
   product varchar(50)
);

insert into t1 values
(1, 'A', 'Product 1'),
(2, 'A', 'Product 2'),
(3, 'A', 'Product 3'),
(4, 'B', 'Product 4'),
(5, 'B', 'Product 5');
What happens if we execute the following query in both Sql Server and PostgreSQL? 
select id, 
category, 
string_agg(product, ';')
                 over (partition by category order by id
                 rows between unbounded preceding and unbounded following) as stragg
from t1;

See possible answers