Function for Proper Case - Most easiest way
This function is used to manage the alphabet case, which means the first letter of all the words will be in caps.
2014-11-26 (first published: 2014-11-03)
1,297 reads
This function is used to manage the alphabet case, which means the first letter of all the words will be in caps.
2014-11-26 (first published: 2014-11-03)
1,297 reads
This script is used to identify the missing sequence numbers or identity numbers.
2014-11-20 (first published: 2014-10-29)
1,123 reads
2014-11-19 (first published: 2014-10-29)
1,143 reads
This script will upload the latest backup files to an AWS S3 bucket
2014-11-14 (first published: 2014-09-14)
1,783 reads
List user connections and possibly any linked server connections older than 1 hour
2014-11-13 (first published: 2014-10-22)
1,719 reads
2014-11-11 (first published: 2014-07-25)
2,707 reads
2014-11-10 (first published: 2014-10-01)
1,378 reads
2014-11-06 (first published: 2014-09-02)
2,505 reads
2014-11-04 (first published: 2014-10-06)
1,392 reads
2014-10-29
1,197 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
WhatsApp CS 628218520154 Jl. Suryopranoto No.40, RT.12/RW.7, Petojo Utara, Kecamatan Gambir, Kota Jakarta Pusat,...
WhatsApp CS 628218520154 Jl. Pegangsaan Timur No.1, Cikini, Kec. Menteng, Kota Jakarta Pusat, Daerah...
WhatsApp CS 628218520154 Jl. Pintu Air Raya No.36 Q, RT.6/RW.1, Ps. Baru, Kecamatan Sawah...
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers