External Article

Work Around Errors in Database Web Apps

ne of the issues you face when building Web applications is handling the errors you encounter when interacting with a back-end database. I was recently working with someone to create a new Web site with SQL Server™, ActiveX® Data Objects (ADO), and ASP. Lots of little things came up that I thought were worth sharing with MIND readers, so I'll focus this column on what I learned from this experience and the solutions to many of the problems I faced.

Technical Article

Quarter of a Century Competition on P2P

P2P, the programmer's resource centre from Wrox Press, reached a milestone of 25,000 subscribers this week. To celebrate this fact, Wrox are giving away $1000 worth of books and ASPToday subscriptions in a free prize draw. For more details on how to enter, please visit: http://p2p.wrox.com/25k.asp. The draw will be made on July 16th.

Blogs

Troubleshooting SQL Server – Starting with the Error Log

By

We’ve all been there. Someone walks up and asks, “Is SQL Server having issues?”...

From OLTP to Analytics: Bridging the Gap with Modern SQL Architectures

By

In the beginning, there was OLTP – Online Transaction Processing. Fast, reliable, and ruthlessly...

Solving SQL Server Mysteries with a Whole Gang of Sleuths -Scooby Dooing Episode 4

By

One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...

Read the latest Blogs

Forums

SQL Server 2025 Jobs

By Do

Hello SQL Server 2022 16.0.4212.1 running on a Windows Server 2025 Std,V 24H2, SO...

how to optimise whole database full of table and sp in one go using githubcopilo

By rajemessage 14195

i have subscription of github copilot which i can access in vs 2022 comunity...

Password Guidance

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Password Guidance

Visit the forum

Question of the Day

Using table variables in T-SQL

What happens if you run the following code in SQL Server 2022+?

declare @t1 table (id int);

insert into @t1 (id) values (NULL), (1), (2), (3);

select count(*)
from @t1
where @t1.id is distinct from NULL;
 

See possible answers