Viewing 15 posts - 13,231 through 13,245 (of 13,849 total)
No it doesn't.
From BOL:
COUNT(*) returns the number of items in a group, including NULL values and duplicates.
COUNT(ALL expression) evaluates expression for each row in a group and returns the number...
November 2, 2005 at 1:26 pm
This is a weird one. Have you run dbcc checkdb?
Also, if you run the statement directly through QA (rather than as part of a stored proc), do you get the...
November 2, 2005 at 12:20 pm
As soon as you put a count() in your query, SQL Server assumes that you are attempting to summarise your data in some way. In particular, it assumes that you...
November 2, 2005 at 10:30 am
Have you tried using DTS? That should do it.
November 2, 2005 at 10:23 am
If you are using QA, check out the value of Tools/Options/Results/Maximum characters per column.
November 2, 2005 at 10:12 am
I am not familiar enough with Access projects to give you a definitive answer here.
Is the selection method something which you have control of? Or is it an off-the-shelf Access...
November 1, 2005 at 8:13 am
Even though they are sharing the program, they are not sharing processes. Is the selection you are talking about performed at run time, or is it driven by data which...
November 1, 2005 at 7:56 am
Are you concerned that multiple user access will cause locking problems?
When you talk of a user's records showing up on other users' reports, what do you mean? Do users own certain...
November 1, 2005 at 7:39 am
Check out INSERT INTO and SELECT INTO in BOL - they will both insert records into a table.
November 1, 2005 at 7:35 am
Don't know, but your query could be rewritten using joins:
delete ta
from TaxAddress ta join Parcel pa on ta.parcelid = pa.parcelid
join CvtMadParcel cmp on pa.userdefinedid = cmp.parcel_no
where pa.taxyear = 2004
Might be...
November 1, 2005 at 7:32 am
Thanks Sushila. I think that my main difficulty here is that I need the ranking (1-5 date desc) built in to the query and I cannot see how to do...
October 25, 2005 at 6:49 am
Or restore a copy of the db from a month ago and use a third-party differencing program to compare this db with the current version and highlight schema differences.
October 24, 2005 at 11:17 am
From EM, click on Management and right click SQL Server Agent. Select Properties - you can view and modify the info here.
October 24, 2005 at 10:49 am
Is this link relevant? Sounds like similar problems ...
http://www.dbforums.com/showthread.php?threadid=986743&perpage=15&pagenumber=1
October 24, 2005 at 7:54 am
You've done it right. I do this often - the backup should be fine (it's also worth zipping the backup before you send it - you'll see the file size...
October 24, 2005 at 7:42 am
Viewing 15 posts - 13,231 through 13,245 (of 13,849 total)