Viewing 15 posts - 346 through 360 (of 1,464 total)
...
He hasn't quite figured out how to tell us when he needs to go potty, so all we can do is get him seated on it until he goes....
June 17, 2020 at 4:43 am
WOW!! My problems with this quarantine are nothing, compared to yours! I'm very sorry you have to put up with all of that.
Thanks Rod.
At the risk of turning this...
May 21, 2020 at 7:12 am
We had a cruise booked. Then came a hard lock-down, so our cruise was cancelled.
We are confined to our homes - Only allowed to go out to purchase groceries or...
May 19, 2020 at 3:18 pm
CREATE TABLE [dbo].[A]([DatabaseName] [nvarchar](1000) NULL, [DBSize] [nvarchar](1000) NULL)
insert into A values (DatabaseA , 580960.00 MB)
insert into A values(DatabaseB, 23523.00 GB)
insert into A values(DatabaseC,234.00 KB)
Table values:
DatabaseA 580960.00...
May 12, 2020 at 7:53 am
You are going to have to check the joins. Without knowing your tables and data, I have attempted to change the joins, so that I can add the OUTER APPLY...
March 12, 2020 at 2:39 pm
Please see the code below.
Which tables contain the fields countryCode and site_id ?
FROM dbo.
,...
March 12, 2020 at 2:06 pm
Help us out by providing the source table name for each field in the WHERE clause
March 12, 2020 at 1:25 pm
So, what is the name of the view?
Do you really have a table or view name dbo?
March 12, 2020 at 1:20 pm
The structure of yor SQL does not make sense to me. Is this for SQL Server, or some other flavour of SQL?
March 12, 2020 at 1:11 pm
You could keep the function, but change it to an inline TVF, like this
CREATE FUNCTION dbo.Stringmultitypes ( @id int )
RETURNS table
AS
RETURN SELECT Types = CAST(STUFF((
...
March 12, 2020 at 12:46 pm
If the source and destination tables are the same structure, you can swap out the partitions
March 6, 2020 at 4:34 am
Are you truly still using SQL 7 or SQL 2000?
March 2, 2020 at 11:24 am
Is there a way to specify a column name for the IN section of code to keep it dynamic? Otherwise, every time there is a new value in the...
February 6, 2020 at 3:50 pm
SELECT
acc
, COUNT(*) AS numOfAcc
, COUNT(DISTINCT token) AS numOfTokenPerAcc
FROM
dbo.Test1
GROUP BY acc
February 2, 2020 at 5:38 am
Based on your sample data, this returns the same result.
WITH cteData AS (
SELECT t.tid, t.b, t.E, seq.st, seq.nd
FROM...
January 30, 2020 at 10:16 am
Viewing 15 posts - 346 through 360 (of 1,464 total)