Viewing 15 posts - 361 through 375 (of 928 total)
BL0B_EATER (10/6/2015)
October 6, 2015 at 9:03 am
Thanks Rodders,
I'm in Portland for a few days before Seattle, and won't be there until Tuesday.
October 5, 2015 at 6:39 am
At SQL Pass there's usually an SSC night. I'm certain I saw mention of it somewhere but can't find it again.
Could somebody tell me which night it is? Then...
October 5, 2015 at 3:07 am
ps_vbdev (10/1/2015)
I thought i read somewhere that you can move data from one partition to another. So in my example at the end of the year all the data in...
October 1, 2015 at 8:02 am
If I've understood correctly, then option 2 isn't possible. I believe MySQL allows partitions within partitions but I've never looked at it. With SQL Server you can have one partition...
October 1, 2015 at 7:33 am
BL0B_EATER (10/1/2015)
Talking about pork products, any one understand Sausage with Maple? I don't..
I've been to Canada more times than I can recall - maple with pretty much anything. Maple with...
October 1, 2015 at 4:26 am
Edvard Korsbæk (9/29/2015)
snapshots seems to be the answer to my question.
Seems like the examples in the first answers makes it possible to use my express edition, where solution two...
September 29, 2015 at 3:46 am
The Pass Summit schedule is now available:
September 29, 2015 at 1:31 am
That sounds like a nightmare to administer. Do you really have such a varying range of permissions that you'd need a DB account for every user?
In reality I suspect you'll...
September 10, 2015 at 12:43 am
kyagi.jo (9/4/2015)
I am thinking of migrating one of my databases and implementing partitions, and using partition switching to load data quickly, so I'm reading up about it.
For the most...
September 4, 2015 at 7:59 am
Are there any error messages in the job history?
If so, can we see them?
September 3, 2015 at 1:25 am
What's the difference between 'None of the above' and 'Other'?
September 1, 2015 at 2:38 am
Phil Parkin (8/21/2015)
(year(getdate() - 1) * 10000 + month(getdate() - 1) * 100 + day(getdate() - 1));
I had to pick that apart to understand it - it is very...
August 21, 2015 at 6:14 am
I'm sure there are other ways to solve this, but this is what immediately sprang to mind:
WITH CTE AS (
SELECT machineid,
COUNT(machineid) AS IPTotal
FROM testip
GROUP BY machineid
)
SELECT...
August 21, 2015 at 2:55 am
Viewing 15 posts - 361 through 375 (of 928 total)