Viewing 15 posts - 211 through 225 (of 1,082 total)
try putting this after your rollback:
DBCC CHECKIDENT (#T1,reseed,0)
DBCC CHECKIDENT (#T1,reseed)
April 28, 2009 at 8:02 am
this might work, by converting the numeric to varchar instead.
select *
from thangela.NpowerNorthern_v1 a INNER JOIN EPPS.dbo.Customers b ON b.MPANCORE = CAST(a.MPAN1 as VARCHAR)
April 28, 2009 at 7:50 am
are you sure that all your varchar values are numerically compatebly?
April 28, 2009 at 7:48 am
SELECT p.Name, sCost, mCost, hCost, tCost
FROM TProject p
OUTER APPLY (SELECT SUM(Cost) as sCost,idProject FROM TSoftware WHERE idProject = p.idProyect GROUP BY idProject) s
OUTER APPLY (SELECT SUM(Cost) as mCost,idProject FROM...
April 28, 2009 at 2:12 am
Is the project not the top level here.
Also should you query not look like this.
SELECT p.name, SUM(s.cost) AS Software, SUM(m.cost) AS Material, SUM(t.cost) AS Travel, SUM(h.cost)...
April 27, 2009 at 10:05 am
Please could you supply some sample data.
I've added the following data and I don't get any duplicates.
One thing to please check is that there are no duplicate names in your...
April 27, 2009 at 10:02 am
Here is an article that Gail touches on about this topic.
http://sqlinthewild.co.za/index.php/2009/03/19/catch-all-queries/
April 27, 2009 at 6:29 am
[Code]
DECLARE @YourTable TABLE
(ScheduleuserId INT,Userid INT, Status INT)
INSERT INTO @YourTable
SELECT 1, 1, 0 UNION ALL
SELECT 1, 2, 1 UNION ALL
SELECT 1, 3, 2 UNION ALL
SELECT 1, 4, 0 UNION ALL
SELECT...
April 27, 2009 at 5:21 am
be careful, because it isn't always the best option...
April 24, 2009 at 5:02 am
Out of interest which method did you take?
I'm with Jack on this, I have started moving to NOT EXISTS as I also find that I often get better performance...
April 24, 2009 at 4:28 am
just remember that your solution does not take into account time.
so for example if you run the query at 2009-04-21 16:38.59
Then anything before 16:38.59 on the 2009-04-14 will not be...
April 21, 2009 at 9:39 am
Could you post the solution?
this will help any others searching for a similar solution 🙂
April 21, 2009 at 9:23 am
I agree 100% 🙂 I think the tools for your solution have now been provided and working out the last part will provide a good learning platform for you to...
April 21, 2009 at 9:12 am
Try give it a go.
So you here is your current date:
15/01/2009
try and right the code.
What you want to try and do is either.
Make you [TableDate] > currentdate - 7 days...
April 21, 2009 at 9:07 am
Viewing 15 posts - 211 through 225 (of 1,082 total)