May 18, 2011 at 10:35 pm
Thanks for the question 🙂
M&M
May 18, 2011 at 11:54 pm
Thanks for the 2 easy points! 🙂
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May 18, 2011 at 11:57 pm
Good question,
Thanks
May 19, 2011 at 7:11 am
I had to look up what re-entrant meant...
May 19, 2011 at 7:24 am
Nice easy and clearly defined two point question! :w00t:
Thanks Steve!
Guess we won't have hundreds of posts arguing the validity of the answer, the sanity of the behavior, or anything else today. :doze:
I'm going to miss that and STUFF... 😎
May 19, 2011 at 9:32 am
thanks for the question.
Jason...AKA CirqueDeSQLeil
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May 19, 2011 at 11:03 am
Another nice straightforward one.
Two points seems a lot for this one, though.
Tom
May 19, 2011 at 11:12 am
Good question..
May 20, 2011 at 1:52 am
I just googled to see whether this question has any inner (hidden) meaning. As the question was from Steve, I thought it would not be as easy as it is showing?
May 20, 2011 at 8:58 am
LOL, I don't always try to make the questions hard. I typically write 5-10 at once, so I balance them out as easy and hard.
May 20, 2011 at 11:19 am
LOL, I should have looked up what re-entrant meant before answering. Oops. 🙂 That'll learn me.
I wasn't thinking in terms of multiple connections, but the same connection re-entering its own query plan. Oopsies. 😀
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May 23, 2011 at 5:23 pm
Thanks for the question!
May 24, 2011 at 8:43 am
Thanks for the question.
Now could anyone point to an article explaining what re-entrant means?
Best regards,
Best regards,
Andre Guerreiro Neto
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May 24, 2011 at 8:54 am
http://en.wikipedia.org/wiki/Reentrant_%28computing%29
It means the same section of code can be executing from one user (or process) and a second user can then use that same code again and start executing it at that same time. It promotes some scalability, since you need less resources for that section of code.
If it's not re-entrant, then a second copy of the code must be created and resources assigned for the second user to execute it.
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