Help needed in resolving the below SQL

Question

Help needed in resolving the below SQL

grkanth81

Ten Centuries

Points: 1194
More actions
October 28, 2014 at 8:36 pm

#294581

Declare @new table
(employee_id int,
invoice_date datetime,
invoice_id int,
invoice_amount money
)
INSERT into @new
Select 100,'2013-06-27',824,6700
union
Select 100,'2013-06-27',824,-6700
union
Select 100,'2013-10-31',839,4800
union
Select 100,'2013-10-31',839,-4800
union
Select 100,'2014-03-31',857,9400
union
Select 100,'2014-08-28',857,-9400
union
Select 100,'2014-08-18',868,16900
union
Select 100,'2014-08-20',868,-16900
Select * from @new
order by invoice_id,invoice_amount desc
When i run the above query the result set would be:
employee_idinvoice_dateinvoice_idinvoice_amount
1002013-06-27 00:00:00.0008246700.00
1002013-06-27 00:00:00.000824-6700.00
1002013-10-31 00:00:00.0008394800.00
1002013-10-31 00:00:00.000839-4800.00
1002014-03-31 00:00:00.0008579400.00
1002014-08-28 00:00:00.000857-9400.00
1002014-08-18 00:00:00.00086816900.00
1002014-08-20 00:00:00.000868-16900.00
As you can see from the above result set, invoice id's 824 and 839 are reversed on the same date.
So, I would like to write a SQL query to get the information of the invoices that are reversed on different date. (i.e i would like to get invoices 857 and 868 details as output)
Thanks,
grkanth81

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pietlinden SSC Guru Points: 63428 More actions · Answer 1

I think I had to read this about 5 times before i figured out what you were asking... Took a bit to realize that the second invoice is a refund.

How about:

SELECT invoice_id

, IssueDate

, ReturnDate

, Amount

FROM

(SELECT invoice_id

, MIN(invoice_date) AS IssueDate

, MAX(invoice_date) AS ReturnDate

, ABS(invoice_amount) AS Amount

FROM #invoices

GROUP BY invoice_id, ABS(Invoice_amount)) x

WHERE x.ReturnDate>x.issueDate;

Luis Cazares SSC Guru Points: 183698 More actions · Answer 2

Maybe you're looking for something like this:

Select *

from @new n

WHERE invoice_id IN( SELECT i.invoice_id

FROM @new i

GROUP BY i.invoice_id

HAVING MAX( i.invoice_date) > MIN(i.invoice_date))

order by invoice_id,invoice_amount desc;

Luis C.
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