Finding time between 2 dates considering working hours

Question

Finding time between 2 dates considering working hours

Jankhana

Say Hey Kid

Points: 681
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March 15, 2012 at 4:09 am

#265834

Hi All.
I have a scenario in which i need to calculate the time consumed by the user to do a task.
suppose Start Time is : 2012-03-14 10:00 am
and End Time is : 2012-03-15 10:am
and working hours is 7 am to 2 pm
then result should be : 7 hours and not 24 hrs.
I know i did to use DateDiff with case statement but i am not able to frame by T-SQL statements.
Thanks

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Gail Shaw SSC Guru Points: 1004504 More actions · Answer 1

Please post table definitions, sample data and desired output. Read this to see the best way to post this to get quick responses.

http://www.sqlservercentral.com/articles/Best+Practices/61537/

Gail Shaw
Microsoft Certified Master: SQL Server, MVP, M.Sc (Comp Sci)
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Dwain Camps SSC Guru Points: 86908 More actions · Answer 2

C'mon Gila, surely you can be more helpful than that!

DECLARE @fromdate DATETIME

,@todate DATETIME

,@workstart DATETIME

,@workend DATETIME

SELECT @workstart = '2012-03-01 07:00:00', @workend = '2012-03-01 14:00:00'

SELECT @fromdate = '2012-03-14 10:00:00', @todate = '2012-03-15 10:00:00'

SELECT DATEDIFF(hour, @fromdate, @todate) - DATEDIFF(day,@fromdate,@todate)*(24 - DATEDIFF(hour, @workstart, @workend)) As ElapsedWorkHrs

,DATEDIFF(minute, @fromdate, @todate) - 60*DATEDIFF(day,@fromdate,@todate)*(24 - DATEDIFF(hour, @workstart, @workend)) As ElapsedWorkMin

,DATEDIFF(second, @fromdate, @todate) - 60*60*DATEDIFF(day,@fromdate,@todate)*(24 - DATEDIFF(hour, @workstart, @workend)) As ElapsedWorkSec

,DATEDIFF(millisecond, @fromdate, @todate) - 1000*60*60*DATEDIFF(day,@fromdate,@todate)*(24 - DATEDIFF(hour, @workstart, @workend)) As ElapsedWorkMSec

Above suggestion took me about 5 minutes. Perhaps one of the results displayed can be suitably formatted by the client application to report elapsed time used.

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Jankhana Say Hey Kid Points: 681 More actions · Answer 3

Thanks @dwain, that solved my problem. I was struggling in datediff calculations. Thank You.

The Dixie Flatline SSC Guru Points: 53354 More actions · Answer 4

Don't forget about weekends or holidays. You may want to make reference to a calendar table that defines holidays or weekends, so that you're only including hours for valid workdays.

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Joe Old Hand Points: 312 More actions · Answer 5

The previous examples output does not change if you tweak the workstart, workend “minutes” in other words the output is the same if the workend is 2012-03-01 14:00:00 or 2012-03-01 14:30:00 the ElapsedWorkMin will still be 420 regardless when it should be 450.

Here is a similar example; you can scale this to seconds if you wish.

DECLARE

@StartShift DATETIME,

@EndShift DATETIME,

@StartDate DATETIME,

@EndDate DATETIME,

@ShiftMinutes FLOAT,

@DateMinutes FLOAT

SELECT @StartShift = '2012-03-15 07:00:00.000', @EndShift = '2012-03-15 14:30:00.000', @ShiftMinutes = DATEDIFF(minute, @StartShift, @EndShift)

SELECT @StartDate = '2012-03-14 10:00:00.000', @EndDate = '2012-03-15 10:00:00.000', @DateMinutes = DATEDIFF(minute, @StartDate, @EndDate)

SELECT

@StartDate AS StartDate,

@EndDate AS EndDate,

@DateMinutes/60 AS RangeInHours,

(@DateMinutes/60)/24 AS RangeInDays,

@DateMinutes AS RangeInMinutes,

@StartShift AS StartShift,

@EndShift AS EndShift,

@ShiftMinutes * ((@DateMinutes/60)/24)/60 AS ShiftHours,

@ShiftMinutes * (@DateMinutes/60)/24 AS ShiftMinutes

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mtassin SSC-Insane Points: 23099 More actions · Answer 6

The Dixie Flatline (3/15/2012)
Don't forget about weekends or holidays. You may want to make reference to a calendar table that defines holidays or weekends, so that you're only including hours for valid workdays.

I agree with Dixie.

Better to use a Calendar table with the holidays, weekends, and work days defined.

Don't also forget partial work days.... which can be a pain.

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