Calculating age

  • Is most simple:
       DECLARE @Birthday date = '1994/12/10'

        SELECT (CAST(CONVERT(VARCHAR(8), GETDATE(), 112) AS INT) - CAST(CONVERT(VARCHAR(8), @Birthday, 112) AS INT)) / 10000 AS Age

  • ELSSON - Thursday, May 4, 2017 2:46 PM

    Is most simple:
       DECLARE @Birthday date = '1994/12/10'

        SELECT (CAST(CONVERT(VARCHAR(8), GETDATE(), 112) AS INT) - CAST(CONVERT(VARCHAR(8), @Birthday, 112) AS INT)) / 10000 AS Age

    I've not checked some of the possibilities nor have I checked it for performance  but THAT IS mighty interesting especially for how it correctly determines ages when a Leap Day is involved.

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

    Change is inevitable... Change for the better is not.


    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)

  • Jeff Moden - Friday, May 5, 2017 5:53 AM

    ELSSON - Thursday, May 4, 2017 2:46 PM

    Is most simple:
       DECLARE @Birthday date = '1994/12/10'

        SELECT (CAST(CONVERT(VARCHAR(8), GETDATE(), 112) AS INT) - CAST(CONVERT(VARCHAR(8), @Birthday, 112) AS INT)) / 10000 AS Age

    I've not checked some of the possibilities nor have I checked it for performance  but THAT IS mighty interesting especially for how it correctly determines ages when a Leap Day is involved.

    Thanks, this solution is ideal for BI, since the IDs of the dates are numbers of the same (Example "2017/05/05" has ID 20170505), so that the IDs would be used directly. This method is based on mathematics and bit-shift (in this case decimal shift)

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