SQL Saturday #198 - Vancouver
SQL Saturday comes back to Vancouver, BC on Feb 16, 2013. Come join in if you can.
2013-02-11
2,086 reads
SQL Saturday comes back to Vancouver, BC on Feb 16, 2013. Come join in if you can.
2013-02-11
2,086 reads
2013-02-04
1,474 reads
2013-01-21
1,562 reads
A free day of training in the US nation's capital. Come join in if you are nearby.
2012-12-03
1,447 reads
SQL Saturday at the gateway between Europe and Asia. If you are nearby, come join in a free day of SQL Server training and presentations.
2012-11-27
1,348 reads
A free day of training, SQL Saturday comes to Tokyo, Japan. Come have a SQL Server day with fellow data professionals if you can.
2012-11-26
1,330 reads
SQL Saturday in the Ukraine. If you want a free day of training, sign up and attend.
2012-11-19
1,559 reads
A free day of SQL Server Business Intelligence sessions in Tampa, FL tomorrow.
2012-11-16
1,605 reads
A free one day training event in Salt Lake City, Utah on Oct 20, 2012.
2012-10-11
2,057 reads
SQL Saturday comes back to Michigan. Come see Jeff Moden and others talk SQL Server on Sept 22, 2012.
2012-09-12 (first published: 2012-08-22)
2,214 reads
By Vinay Thakur
Continuing from Day 3 where we covered LLM models open/closed and their parameters, Today...
By Steve Jones
One of the nice things about Flyway Desktop is that it helps you manage...
By HeyMo0sh
Microsoft Fabric (not to be confused with the more general term “fabric” in DevOps)...
I'm fairly certain I know the answer to this from digging into it yesterday,...
Hi Team, I am trying to refresh the Azure Synapse Dedicated pool from production...
hi everyone I am not sure how to write the query that will produce...
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT *
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t; See possible answers