2008-08-06
64 reads
2008-08-06
64 reads
2008-08-05
72 reads
Would you leave technology and come back to it as a career? It seems that many people are afraid of doing it, but Steve Jones talks about why it shouldn't matter.
2008-08-04
54 reads
Steve Jones talks about the changing capabilities and flexibilities of data centers as technologies change.
2008-08-03
60 reads
This week's Database Weekly editorial examines the US policy of potentially seizing laptops for an infinite period when you enter the country.
2008-08-02
69 reads
This Friday Steve Jones talks about the social networking phenomenon and asks how it should affect your career?
2008-07-31
64 reads
You are hired for your ideas so share them, it can only help your career.
2008-07-30
60 reads
A guest editorial from Scott White that looks at the use of stored procedures from a developer's point of view.
2008-07-29
72 reads
With the price of gas rising and no end in sight. Steve Jones steps back to talk a bit about what solutions there might be to ease the burdens on everyone.
2008-07-28
502 reads
Steve Jones talks about how IT hasn't changed very much over the years and how your career might not be that different in ten years.
2008-07-27
60 reads
By Steve Jones
It’s time for T-SQL Tuesday again and this is a great prompt to start...
By alevyinroc
T-SQL Tuesday is a monthly blog party hosted by a different community member each...
How I used AI for this postChatGPT to generate images based on info specifically...
Telp/Wa 62 821-8200-233 Jl. H. R. Rasuna Said No.Kav. 01, RW.6, Guntur, Kecamatan Setiabudi,...
Telp/Wa 62 821-8200-203 Koperasi Sejati Mulia, Jl. Raya Ragunan B 1, RT.3/RW.3, Jati Padang,...
Telp/Wa 62 821-8200-174 Gd. Graha Inti Fauzi, Jl. Buncit Raya No.22 Lt. Dasar, RT.2/RW.7,...
Which number will the COUNT() return after executing the following statements:
DROP TABLE IF EXISTS #test; CREATE TABLE #test (id INT) INSERT INTO #test (id) SELECT * FROM GENERATE_SERIES(1, 3) AS gs ; ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0; go UPDATE #test SET flag = 0 WHERE id = 1 UPDATE #test SET flag = 1 WHERE id = 2 INSERT INTO #test (id) VALUES (4) SELECT COUNT(*) FROM #test AS t WHERE flag = 0See possible answers