2022-10-07
498 reads
Administration
2022-10-05
575 reads
[Video] Fragmentation Explained in 20 Minutes at SQLBits
What does fragmentation mean? How does it happen? Can you fix it with fill factor? Should you rebuild your indexes to fix it?
2022-09-26
2022-09-16
369 reads
Understanding the System Function FILEPROPERTY()
Learn how to use the system function, FILEPROPERTY(), to get information about your database in T-SQL.
2022-09-09
4,312 reads
The Case for Patching
Recently I was testing a feature in SQL Server on 2017 and 2019. There was supposed to be an improvement across versions, but I didn't see it. Then I realized that I was on SQL Server 2019 CU 2 on my laptop, and the current CU is 17. I took a few minutes to download […]
2022-08-20
156 reads
Getting More Information From the String or Binary Data Truncated Error
Get more information from the string or binary data truncated message to help troubleshoot data problems on SQL Server 2016, 2017, and 2019.
2022-08-17
9,037 reads
2022-08-03
477 reads
Linked Servers: a Peek Behind the Curtain
Learn how a linked server caused an issue with Gallium Data.
2022-07-15
5,205 reads
2022-07-13
553 reads
Blogs
Prime Day Recommendations
By Steve Jones
It’s Prime Day. A few of my recommendations, since I want to do some...
Fabric for Operational Reporting & SQL Endpoint Trap
With Fabric Mirroring, Microsoft is promoting a nice and appealing story for operational reporting...
Crawl, Walk, Run with Agentic Development of Power BI Assets
If you’ve been watching AI roll through the data community and thinking, “this seems...
Forums
SQL Art, Part 4: Happy 4th of July — A British DBA's Guide to Celebrating a War We Don't Talk About
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
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Question of the Day
Multiple Values Inserted
I have this code on SQL Server 2022. What happens when it runs all at once?
DROP TABLE IF EXISTS dbo.Commission GO CREATE TABLE dbo.Commission (id INT NOT NULL IDENTITY(1,1) CONSTRAINT CommissionPK PRIMARY KEY , salesperson VARCHAR(20) , commission VARCHAR(20) ) GO INSERT dbo.Commission ( salesperson, commission) VALUES ( 'Brian', 12 ), ( 'Brian', 'None' ) GOSee possible answers