Thanks for the Help with Deadlocks
It's time to start blogging again. And for my first post in a very long time, I mainly want to...
2015-05-08 (first published: 2015-05-02)
7,555 reads
It's time to start blogging again. And for my first post in a very long time, I mainly want to...
2015-05-08 (first published: 2015-05-02)
7,555 reads
2015-05-02
10 reads
2015-05-02
10 reads
2015-05-02
6 reads
2015-05-02
18 reads
This session is mostly demo-focused. I will cover prerequisites for scripts and show how to do multiple SQL Server installations using scripts and demonstrate how to Streamline SQL Server...
2015-05-02
17 reads
This session is mostly demo-focused. I will cover prerequisites for scripts and show how to do multiple SQL Server installations...
2015-05-02
644 reads
Join Adam Jorgensen and Pragmatic works to learn about Building Your Data Team’s Make Up and Culture on Tuesday, May 5.
2015-05-01
430 reads
I finally got out to some community events last month and got to see a bunch of great speakers. Not...
2015-05-01
509 reads
A company with more than one SQL Server instance has no built-in way to gather and report on maintenance, backup, and configuration...
2015-05-01
1,241 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers