Determining Default Trace Location
While working on some scripts against SQL Server’s default trace, I wanted to develop a sure fire way to find...
2013-01-09
1,795 reads
While working on some scripts against SQL Server’s default trace, I wanted to develop a sure fire way to find...
2013-01-09
1,795 reads
It’s been a while since I mentioned anything about the SQL Saturday in Fargo. So I thought I would let...
2013-01-08
575 reads
In the past couple weeks, I’ve gotten a couple reports of issues with sp_indexanalysis. The update today fixes those issues....
2013-01-08
744 reads
Today is the first Monday of 2013. Do you know if your servers are ready to take on the first...
2013-01-07
679 reads
Throughout the week, I like to tweet links to the things that I’ve been reading. Since they all come out through out...
2013-01-07
903 reads
Welcome to this Friday’s reblog summary post. The aim of these posts is to bring some old posts that newer...
2013-01-04
1,036 reads
Last year, I did a wrap up post of the year to see where I landed from where I wanted...
2012-12-31
1,629 reads
Throughout the week, I like to tweet links to the things that I’ve been reading. Since they all come out through out...
2012-12-31
1,719 reads
Welcome to this Friday’s reblog summary post. The aim of these posts is to bring some old posts that newer...
2012-12-28
1,108 reads
Last week, I presented on extended events at the Minnesota SQL Server user group (PASSMN). The turnout was quite excellent...
2012-12-28
731 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers