SQLAndy

Blog Post

Fourth of July

Read the Declaration of Independence and then it’s time for fireworks and grilling, maybe some apple pie too!

2009-07-03

504 reads

Blogs

Why your data still can’t answer a simple question 

By

Every organization I talk to has the same problem dressed up in different clothes....

T-SQL Tuesday #197 Invitation – An impactful session or two from a conference

By

I am delighted to host this month’s T-SQL Tuesday invitation. If you are new...

Did You Really Name That Default?

By

Ten years (and a couple jobs) ago, I wrote about naming default constraints to...

Read the latest Blogs

Forums

The day-to-day pressures of a DBA team, and how we can work smarter with automation and AI

By Terry Jago

Comments posted to this topic are about the item The day-to-day pressures of a...

Using OPENJSON

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Using OPENJSON

Data Modeling with dbt for Visual Code: The Fabric Modern Data Platform

By John Miner

Comments posted to this topic are about the item Data Modeling with dbt for...

Visit the forum

Question of the Day

Using OPENJSON

I have some data in a table that looks like this: 

BeerID BeerName    brewer               beerdescription
1      Becks       Interbrew            Beck's is a German-style pilsner beer 
2      Fat Tire    New Belgium          Toasty malt, gentle sweetness, flash of fresh hop bitterness.
3      Mac n Jacks Mac & Jack's Brewery This beer erupts with a floral, hoppy taste
4      Alaskan Amber Alaskan Brewing     Alaskan Brewing Amber Ale is an "alt" style beer
8      Kirin       Kirin Brewing         Kirin Ichiban is a Lager-type beer
If I run this, what is returned? 
select t1.key
    from openjson((select t.* FROM Beer AS t for json path)) t1

See possible answers