Speaking at SQL Saturday Atlanta (#733)
I am so honored and humbled to have been selected to speak at SQL Saturday Atlanta (#733) on May 19,...
2018-03-29
396 reads
I am so honored and humbled to have been selected to speak at SQL Saturday Atlanta (#733) on May 19,...
2018-03-29
396 reads
Two Saturdays ago, I was in Reykjavik, Iceland, speaking at my very first international SQL Saturday. WOW! Is all I...
2018-03-19
608 reads
SQL Saturday Richmond is just 5 days away and this will be the second time I have been selected to...
2018-03-19
241 reads
My grandfather used to say, “There’s more than one way to skin a cat.” I always thought it was a...
2018-03-08 (first published: 2018-03-02)
4,727 reads
I am so excited, I was selected to speak at SQL Saturday Richmond on March 24, 2018, in Richmond, Virginia.
SQL...
2018-02-06
261 reads
I can finally breath a sigh of relief, my first time of presenting two sessions back to back is finally...
2018-02-06
251 reads
I am so excited to announce that I have been accepted as a speaking mentor on SpeakingMentors.com!
I struggled for so...
2018-01-31
482 reads
Holy Cow! I still can’t believe it, I was awarded the Microsoft MVP – Data Platform today. I guess I really...
2018-01-04
603 reads
Back in 2015, I said would think about speaking in my #TSQL2sday #61 post. Well here it is 2018 and...
2018-01-03
382 reads
I started speaking on a semi-regular basis this year after many years of trepidation. You can read about my first...
2017-11-17
300 reads
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
SELECT * feels convenient, but in SQL Server it bloats I/O, burns network bandwidth,...
Comments posted to this topic are about the item Cleaning Up the Cloud
Comments posted to this topic are about the item The Maximum Value in the...
Comments posted to this topic are about the item Oracle Performance Tuning: Practical Techniques...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers