Las Vegas UG This week
What a fun week we have tuned up for the folks in Las Vegas. It is the first full week...
2015-01-05
537 reads
What a fun week we have tuned up for the folks in Las Vegas. It is the first full week...
2015-01-05
537 reads
What a fun week we have tuned up for the folks in Las Vegas. It is the first full week of January and there is this huge convention going...
2015-01-05
Reading a Microsoft Article (which can be found here) while making sure I understood what can cause a query plan to...
2015-01-07 (first published: 2015-01-05)
7,887 reads
Some effects on plan cache and max memory settings
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2015-01-05
Quick and simple for today. Happy Holidays to you!
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2014-12-26
637 reads
Quick and simple for today. Happy Holidays to you!
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2014-12-26
Tis the season for TSQL Tuesday. Not only is it that season again, but it is also the Holiday season.
During...
2014-12-09
748 reads
Tis the season for TSQL Tuesday. Not only is it that season again, but it is also the Holiday season. During this season, many people start to think about...
2014-12-09
This past weekend I had the opportunity to go visit Washington DC. It was just the second time I got to...
2014-12-08
542 reads
This past weekend I had the opportunity to go visit Washington DC. It was just the second time I got to stay in the Nation’s capitol for more than just...
2014-12-08
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers