December 2011 LV UG Meeting
The Holidays are upon us. It is time to take a break from the hustle and bustle and come out...
2011-11-30
1,633 reads
The Holidays are upon us. It is time to take a break from the hustle and bustle and come out...
2011-11-30
1,633 reads
The Holidays are upon us. It is time to take a break from the hustle and bustle and come out to participate in the local User Group for SQL...
2011-11-30
12 reads
Back in August, I published a post on exporting SSRS report files en masse. That article (which can be read...
2011-11-29
1,701 reads
Pro-tip on how to quickly and easily migrate data sources for reporting services.
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2011-11-29
19 reads
Since Deep Dives 2 came out, I had been putting off getting my copy of the e-book until I wanted...
2011-11-23
790 reads
Since Deep Dives 2 came out, I had been putting off getting my copy of the e-book until I wanted the book for travel purposes. I decided I really...
2011-11-23
9 reads
Finally, I have completed another book. I took the opportunity while traveling to catch up on some reading. Better yet,...
2011-11-22
641 reads
Finally, I have completed another book. I took the opportunity while traveling to catch up on some reading. Better yet, I was able to do this while testing out...
2011-11-22
13 reads
At the beginning of the month, we had a Meme Monday on the topic of SQL Family. I had a...
2011-11-21
667 reads
At the beginning of the month, we had a Meme Monday on the topic of SQL Family. I had a few things to say about the SQL community back...
2011-11-21
12 reads
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Comments posted to this topic are about the item Let's Talk Certifications
Comments posted to this topic are about the item The Hidden Security Risks of...
Comments posted to this topic are about the item The Empty Aggregate
I have this table in a SQL Server 2025 database:
CREATE TABLE [dbo].[CustomerOrder] ( [OrderID] [int] NULL, [CustomerID] [int] NULL, [total] [money] NULL ) ON [PRIMARY] GOWhat is returned from this code? (answers are for the sum and then the count)
SELECT SUM(total) AS sum,
COUNT(total) AS count
FROM dbo.CustomerOrder;
See possible answers