SQLCLR vs. SQL Server 2017, Part 2: “CLR strict security” – Solution 1
As mentioned in Part 1 of this “SQLCLR vs. SQL Server 2017” series, the new clr strict security server-level configuration...
2017-08-09
959 reads
As mentioned in Part 1 of this “SQLCLR vs. SQL Server 2017” series, the new clr strict security server-level configuration...
2017-08-09
959 reads
The Good, the Bad, and the Ugle¯e¯ (need to avoid copyright infringement ?? )
SQL Server 2017 is soon to be officially...
2017-08-07
2,347 reads
In SQL Server Management Studio (SSMS), there are a lot of options and functions. In fact, there are so many...
2017-07-20
2,106 reads
SQL Server Management Studio (SSMS) for SQL Server 2016 added some interesting enhancements for the vertical scroll bar: Map Mode...
2017-07-17
641 reads
Quite often people will use, or will recommend using, a binary Collation (one ending in “_BIN” or “_BIN2“) when wanting...
2017-07-13
2,121 reads
You may have heard, or read, that you should not mix VARCHAR and NVARCHAR datatypes, especially when one of them...
2017-07-10
5,110 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Comments posted to this topic are about the item The AI Bubble and the...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers