A New Identity
Well, perhaps not a whole new identity, just a consolidation of multiple facets of my online persona. For several years...
2009-08-23
544 reads
Well, perhaps not a whole new identity, just a consolidation of multiple facets of my online persona. For several years...
2009-08-23
544 reads
As I was going through some of my documentation at past clients, I found my summary of the general SOX...
2009-08-23
2,469 reads
I wrote last month about purchasing a new Toshiba netbook to supplement my mobile computing arsenal. Forty days later, I’m...
2009-08-22
617 reads
I realize I have been relatively quiet for a while, but summer is actually a fairly busy time for us...
2009-08-22
1,222 reads
Okay, Jorge Segarra (@SQLChicken) tagged me in Chris Shaw’s (@SQLShaw) latest SQL Quiz, SAN’s and Mirroring. I’m a little behind...
2009-08-21
338 reads
If you live in Australia, or are just looking for an excuse for a vacation in Australia, sign up for...
2009-08-21
679 reads
Microsoft has released the latest Cumulative Update for SQL Server 2005 SP3, which is Build 4230. They also released a...
2009-08-21
485 reads
In a recent forum thread, someone asked to see who created/altered a particular object. Starting in SQL Server 2005, this information is...
2009-08-21
1,419 reads
I saw this question and my immediate thought was “Well, duh, the execution plan is recreated by a recompile.” But,...
2009-08-21
1,331 reads
Baton Rouge SQL Server group leader and recent SQL Saturday host Patrick LeBlanc is putting together a new learning series. ...
2009-08-21
710 reads
When I put together the invitation for T-SQL Tuesday #202, I wasn't sure what...
By Steve Jones
My life has some crazy travel stretches for sure. Between speaking, office visits, customer...
In Part 1, we saw how ‘Vamana’ represents vectors as nodes, connects them with...
Comments posted to this topic are about the item Server-Level Table sizes
Comments posted to this topic are about the item Optional Parameter Plan Optimization in...
There is a table tmp_tab:
CREATE TABLE tmp_tab ( id int, val int );
INSERT INTO tmp_tab VALUES (1, 1), (2, NULL), (3, 3), (4, 4), (5, 5);You want to order the rows ids by the following expression:
ISNULL(val, id) + 1Which of the following queries produces the expected ordering and why? (Select all correct) See possible answers